3.26d+9.75d−2.65 help pl

Add  3.26 d  and  9.75 d . 13.01 d − 2.65

Step-by-step explanation:

13.01d-2.65

Step-by-step explanation:

Since you have to simplify it you have to get rid of them so just add 3.26d+9.75 and you get 13.01d and the  minus 2.65

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.