Jeremy's coach makes him run clockwise around a circular track with radius of 50 meters. Jeremy manages to maintain a constant speed around the track. He takes 48 seconds to finish one lap of the track. From his starting point, it takes him 12 seconds to reach the northernmost point of the track. Answer the following questions below assuming that the center of the track at the origin and the northernmost point is on the y-axis. a. Give Jeremy's coordinates at his starting point.
b. Give Jeremy's coordinates when he has been running for 4 seconds.
c. Give Jeremy's coordinates when he has been running for 32 seconds.

Coordinates of the starting point ( -50 ; 0 )

Coordinates 4 seconds later Q ( - 25*√3  ;  25 )

Coordinates 32 seconds later R ( 25  ;  - 25*√3 )

Step-by-step explanation:

a) If Jeremy takes 48 seconds fr a lap then

The length of the lap ( length of the circle ) is:

L =  2*π*r    ⇒   L = 100*π

If the time for one lap was 48 seconds at a constant speed, the speed was

v = 100*π / 48   [m/s]

v = 6,54 m/s

12 seconds  is  1/4 0f 48  in that time he (she) reach the northernmost point, then he(she) necessarily started on the negative side of the       x-axis the coordinates at this point are

( -50 ; 0 )

b) 4 seconds later, at v = 6,54 m/s by rule of three

In 12 seconds                         90⁰

In  4  seconds  (the third part )       x ??

x = 30⁰

sin 30⁰  = 1/2

cos 30⁰ = (√3)/2

And coordinates for the point are

sin 30⁰ =  1/2  = y/50     ⇒  y =  25

cos 30⁰ = (√3)/2  = x / 50   ⇒ x = 25*√3

coordinates of the point 4 seconds later

Q ( - 25*√3  ;  25 )    she (he) is in the negative part of x-axis

c) 32 seconds later

32  is    12   +   12    +    8

Then she (he) is 8 seconds below the positive side of x-axis

8 is 2/3 of 12   ( negative 60⁰ )

sin 60⁰ = (√3)/2   = y/50       y  =  25*√3    negative

cos  60⁰ = 1/2 * 50   =  X/50  x  = 25

Coordinates of the point R

R ( 25  ;  - 25*√3 )

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %