For each of the following vector fields F, decide whether it is conservative or not by computing the appropriate first order partial derivatives. Type in a potentialfunction f (that is, ∇f = F) with f(0,0)=0. If it is not conservative, type N.
A. F(x, y)=(−16x+2y)i+(2x+10y) j f(x, y)=
B. F(x, y)=−8yi−7xj f(x, y)=
C. F(x, y)=(−8sin y)i+(4y−8xcosy)j f(x, y)=

(A)

(B)

But we assume is a function of alone, so there is not potential function here.

(C)

For (A) and (C), we have , which makes for both.

answer: haha (: i’ll go see what it is

step-by-step explanation:

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.