Mathematics, 18.08.2020 06:01 cyndiann2002

The house Trevor's family lives in has 666 people (including Trevor) and 333 bathrooms. In the past month, each person showered for an average of 480480480 minutes and used an average 727272 liters of shower water (over the entire month). Water costs 0.200.200, point, 20 dollars per liter. How much did Trevor's family pay per minute on shower water?

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Answer from: SkylarAaliyah

Using proportions, we find that: Trevor's family paid $0.03 per minute on shower water.

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This question is solved using proportions.

There are 6 people in the house.There are 3 bathrooms in the house.Each person used an average of 72 liters of shower.

Thus, the total amount of liters used is:

$L = 72 \times 6 = 432$

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432 liters used.Each liter costs $0.2.

Thus, the total amount paid was of:

$A = 432 \times 0.2 = 86.4$

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Total of 86.4 dollars.Total of 6x480 = 2880 minutes.

The amount of dollars per minute is:

$D = \frac{86.4}{2880} = 0.03$

Trevor's family paid $0.03 per minute on shower water.

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Answer from: breemills9953

Trevor's family paid $ 1.33 per minute on shower water.

Since the house Trevor's family lives in has 6 people (including Trevor) and 3 bathrooms, and in the past month, each person showered for an average of 480 minutes and used an average 72 liters of shower water (over the entire month), and water costs 0.20 dollars per liter, to determine how much did Trevor's family pay per minute on shower water, the following calculation must be performed:

You must multiply the number of liters by its value, and divide that result by the number of minutes that each person consumed, in order to obtain the value per minute on shower water.

((480 x 6) x 0.2) / (6 x 72) = X(2880 x 0.2) / 432 = X576/432 = X1.333 = X

Therefore, Trevor's family paid $ 1.33 per minute on shower water.

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The house Trevor's family lives in has 666 people (including Trevor) and 333 bathrooms. In the past

Answer from: Quest

step-by-step explanation:

Answer from: Quest

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!