Let a be -1/6 and let b be 1/2. Let x be the sum of the reciprocals of a and b, let y be the product of the reciprocals of a and b, and let z be twice the reciprocal of a divided by the reciprocal of b. Calculate x+y+z. Please Help!

x + y + z = - 22

Step-by-step explanation:

Reciprocal of a : - 6,

Reciprocal of b : 2

Therefore if x is the sum of the reciprocals of a and b, it will be - 6 + 2 = - 4. x will be - 4.

Respectively if y is the product of the reciprocals of a and b, it will be - 6 2 = - 12. y is - 12. And if z is twice the reciprocal of a / the reciprocal of b, it will be the following,

z = 2(- 6) / 2

= - 12 / 2 = - 6

And x + y + z = - 4 - 12 - 6 = - 22. That is your solution.

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation:

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b