Factor the trinomial below. x2 + 3x - 18
A. (x + 6)(x-3)
B. (x+9)(x-2)
C. (X-9)(x+2)
D. (x-6)(x+3)

( x+6) ( x-3)

Step-by-step explanation:

x^2 + 3x - 18

What 2 numbers multiply to -18 and add to 3

6*-3 = -18

6+-3 = 3

( x+6) ( x-3)

A

Step-by-step explanation:

Given

x² + 3x - 18

Consider the factors of the constant term (- 18) which sum to give the coefficient of the x- term (+ 3)

The factors are + 6 and - 3, since

6 × - 3 = - 18 and 6 - 3 = + 3, thus

x² + 3x - 18 = (x + 6)(x - 3) → A

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2