Leslie was able to map \overline{ST} ST start overline, S, T, end overline onto \overline{QR} QR start overline, Q, R, end overline using a rotation and dilation. Leslie concluded: "I was able to map \overline{ST} ST start overline, S, T, end overline onto \overline{QR} QR start overline, Q, R, end overline using a sequence of rigid transformations, so the figures are congruent." What error did Leslie make in her conclusion?

The fact that Leslie used a dilation is where she made the mistake. A dilation either shrinks or enlarges a figure. So it made segment ST either larger or smaller to be able to fit to segment QR.

But congruent segments are always the same length. So there's no way that a dilation can be involved. Only rigid transformations of translations (aka shifting), reflections, and rotations are allowed. A dilation is not a rigid transformation.

answer: 88

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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