Find the value of x. A. 3 B. 2 C. 5 D. 6

Step-by-step explanation:

Apply the intersecting chord theorem.

DK × BK = AK × CK

12(4x+1) = 14(3 + 3x)

Expand brackets.

48x + 12 = 42 + 42x

Subtract 42x and 12 from both sides.

6x = 30

Divide both sides by 6.

x = 5

C

Step-by-step explanation:

Given 2 chords intersecting inside a circle, then

the product of the measures of the parts of one chord is equal to the product of the measures of the parts of the other chord, that is

12(4x + 1) = 14(3 + 3x) ← distribute parenthesis on both sides

48x + 12 = 42 + 42x ( subtract 42x from both sides )

6x + 12 = 42 ( subtract12 from both sides )

6x = 30 ( divide both sides by 6 )

x = 5

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

9

step-by-step explanation: