Let ABCD be a parallelogram such that AB = 10,BC = 14, and \angle A = 45. Find the area of the parallelogram. please write your answer as a root. NOT a decimal.

Explanation:

One formula you can use is

A = b*c*sin(theta)

where angle theta is between sides b and c

Note how angle A is between sides AB = 10 and AD = BC = 14.

Using that formula gives

A = b*c*sin(theta)

A = 10*14*sin(45)

A = 140*sin(45)

A = 140*sqrt(2)/2 ... use unit circle

A = (140/2)*sqrt(2)

A = 70*sqrt(2)

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.