Let ABCD be a parallelogram such that AB = 10 , BC = 14, and Angle A = 45. Find the area of the parallelogram. Will make person brainliest if answered within 15 minutes and is correct.

Area of a parallelogram is base times height. Note that CD = AB & AD = BC

to find the height, draw a line from angle B perpendicular to the base b. Lets call the point of intersection at the base E. This constitutes a right triangle with AB as the hypotenuse. Using the law of sine to calculate the height h:

h/sin(A) = AB/sin(90°) ( sin(90°) = 1)

h = AB * sin(45°)

h = 10 * sin(45°)

Area = 14 * 10 * sin(45°) = 140 * sin(45°) ≈ 98.99 QEDexplanation:

if x = 1, then the answer is 3.5

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: