The diagonals of a rhombus are 16cm and 12cm long. Calculate the length of its side

10 cm

Step-by-step explanation:

The diagonals of a rhombus are perpendicular bisectors of each other.

All sides are congruent.

The diagonals divide the rhombus into 4 congruent right triangles.

Applying Pythagoras' identity to 1 of the triangles with legs 6 and 8 and hypotenuse the side s of the rhombus, then

s² = 6² + 8² = 36 + 64 = 100 ( take the square root of both sides )

s = = 10

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb