What is the area, in square inches, of the isosceles trapezoid below? 17.9 in
18 in
8.3 in

104.8 in^2

Step-by-step explanation:

There are 2 ways to solve this problem.

The 1st way:

Let's make 2 triangles and 1 rectangle:

Rectangle Length = 8.3

Rectangle Width = 8

So, the left out length will be 17.9 - 8.3

=> 9.6

Since, 9.6 cm is for 2 parts.

=> 9.6 / 2

=> 4.8

So, Height of the Triangle = 8

      Base of the triangle = 4.8

Area of a rectangle

=> 8.3 x 8

=> 66.4

Area of the triangle

=> 1/2 x 8 x 4.8

=> 4 x 4.8

=> 19.2

There are 2 triangles:

=> 19.2 x 2

=> 38.4

=> 66.4 + 38.4

=> 104.8

The area of the trapezoid = 104.8 in^2.

The 2nd way is:

Area of a trapezoid

=> Smaller Base + Larger Base / 2 x Height

=> 8.3 + 17.9 / 2 x 8

=> 26.2 / 2 x 8

=> 13.1 x 8

=> 104.8

The area of the trapezoid is 104.8 in^2

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: