Select the third function, y = 2 cos(x),
and set the interval to [−4.01, 4.01].
(a) With 10 rectangles using left endpoints, how many rectangles are contributing negative area values to the estimated net area?
How many are positive?
(b) What is the error when using midpoints with 10 subintervals? (Do not round your answer.)
What is the ratio of the left-endpoint approximation error to the midpoint error? (Round your answer to two decimal places.)
(c) Of the available choices, how many subintervals are required to give a midpoint approximation accurate to 2 decimal places?

-2

7 - 9 = -2

reversed:

-2 + 9 = 7

hope this !

let me know

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

step-by-step explanation:

what was your answer?