Which statement is true about this equation? 3(-y + 7) = 3(y + 5) + 6 A. The equation has one solution, y = 0. B. The equation has one solution, y = -1. C. The equation has no solution. D. The equation has infinitely many solutions.

y=0 So its A

Step-by-step explanation:3(-y+7)=3(y+5)+6

We move all terms to the left:

3(-y+7)-(3(y+5)+6)=0

We add all the numbers together, and all the variables

3(-1y+7)-(3(y+5)+6)=0

We multiply parentheses

-3y-(3(y+5)+6)+21=0

We calculate terms in parentheses: -(3(y+5)+6), so:

3(y+5)+6

We multiply parentheses

3y+15+6

We add all the numbers together, and all the variables

3y+21

Back to the equation:

-(3y+21)

We get rid of parentheses

-3y-3y-21+21=0

We add all the numbers together, and all the variables

-6y=0

y=0/-6

y=0

3x^3-x^2+6x-9

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation: