Find the product. 2√3•√15 A)5√5 B)√45 C)6√5 D)18√5

First multiply the numbers inside the radicals together.

So √3 · √15 is √45.

So we have 2√45.

Note that the 2 can't be multiplied by anything since

√15 has nothing outside of the radical.

So we have 2√45.

Now, break down your square root.

√45 breaks down as 9 · 5 and 9 breaks down as 3 · 3.

Since we have a pair of 3's, a 3 comes outside of the radical

multiplying by the 2 that was previously outside to get 6.

The 5 doesn't pair up so it stays inside.

So our final answer is 6√5.

45

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