Lea left home and drove toward the ferry office at an average speed of 22 km. H. Trevon left at the same time and drove in the opposite direction with an average speed of 43 km/h. How long does Trevon need to drive before they are 65 km apart?

1 hour

Step-by-step explanation:

Lea's speed = 22km/hr

Trevon's speed = 43km/hr in a direction opposite Lea's

How long does Trevon needs to drive before they are 65km apart.

Note : both took at the same time and in opposite direction.

Recall : speed = distance / time

Distance = speed * time

Distance between them = 65km

Let Trevon's distance = D2 = 43 * t

Lea's distance = D1 = 22 * t

t is the same since they both left at the same time.

D2 + D1 = 65

43t + 22t = 65

65t = 65

t = 65/65

t = 1 hour

geometry: triangles

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lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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