Wyatt is going to a carnival that has games and rides. Each game costs $1.25 and each ride costs $2.75. Wyatt spent $20.25 altogether at the carnival and the number of rides he went on is twice the number of games he played. Determine the number of games Wyatt played and the number of rides Wyatt went on.

Wyatt played 3 games and went on 6 Rides

Step-by-step explanation:

Let games be represented as x

Let ride be represented as y

Each game cost $1.25

Each ride cost $2.75

Total money spent by Wyatt= $20.25

x1.25 + y2.75 = 20.25 Equation 1

the number of rides he went on is twice the number of games he played

Y= 2x ... Equation 2

Substituting the value of y into equation 1

x1.25 + y2.75 = 20.25

x1.25 + 2(x)2.75 = 20.25

x1.25 + x5.5 = 20.25

x6.75= 20.25

x= 20.25/6.75

X= 3

Y= 2x

Y= 2(3)

Y= 6

Wyatt played 3 games and went on 6 Rides

uhhh idk u yolo?

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204