The expression 100 + 20m100+20m100, plus, 20, m gives the volume of water in Eduardo's pool (in liters) after Eduardo spends mmm minutes filling his pool. What is the volume of water in Eduardo's pool after he fills it for 5 \dfrac145 4 1 5, start fraction, 1, divided by, 4, end fraction minutes?

205 litres

Step-by-step explanation:

Given:

Volume of water is given as:

(in litres)

m is the time in minutes spent filling water in Eduardo's pool.

To find:

Volume of water in the pool after the water is filled for minutes.

Solution:

Here, volume of water in the Pool (in litres) is given by the equation:

....... (1)

Where m is the time for which Eduardo fills the pool.

Here, we are also given that

m = minutes = minutes

And we have to find the value of V after minutes.

Let us put the value of m as minutes in the equation (1) to find the value of V.

So, the volume of water in the pool after minutes is 205 litres.

the slope of the first function is -3. (3/1)

the slope of the second function is 1. (13-10/6-3).

since |-3| is greater than |1|, the function with the steepest slope is the first.