A suitcase has a lock on it consisting of four numbers. Each number could be any number 0-9. The only restriction is that the last slot has to be an even number.

We have 5000 possible combinations.

Step-by-step explanation:

I guess that we want to find the possible combinations for this lock.

We have 4 numbers, so we have 4 selections.

Now, let's count the number of options in each selection.

in the first selection, we have 10 options (0, 1, 2, 3, 4, 5, 6, 7, 8 and 9)

in the second selection, we have 10 options (0, 1, 2, 3, 4, 5, 6, 7, 8 and 9)

in the third selection, we have 10 options (0, 1, 2, 3, 4, 5, 6, 7, 8 and 9)

in the last selection, we have 5 options (0, 2, 4, 6 and 8)

The total number of combinations is equal to the product of the number of options in each selection:

C = 10*10*10*5 = 5000 combinations.

we need the options

step-by-step explanation:

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: