Let f () = x^2, g(x) = 2x – 1. and h (x)= x-4
Evaluate h(g(-5)).?

-15.

Step-by-step explanation:

G(-5) = 2(-5) - 1

= -10 - 1

= -11

H(-11) = -11 - 4

= -15

Hope this helps!

h(g(-5))= -15

Step-by-step explanation:

We are asked to find h(g(-5)).

First, we must find g(-5).

We know that g(x)=2x-1. Therefore, to find g(-5), we must plug -5 in for x.

g(x)= 2x-1

g(-5)= 2(-5) -1

Multiply 2 and -5.

g(-5)= -10 -1

Subtract 1 from -10.

g(-5)= -11

Now, we can substitute -11 in for g(-5).

h(g(-5)

g(-5)= -11

h(-11)

Now, we must find h(-11).

We know that h(x)= x-4. So, we can plug -11 in for x.

h(x)= x-4

h(-11)= -11-4

Subtract 4 from -11.

h(-11)= -15

h(g(-5)=  -15

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step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !