Thirteen people on a sports team show up for a game. a. How many ways are there to choose 10 players to play the game? b. How many ways are there to assign the 10 different positions by selecting players from the 13 who show up?

a)286 ways

b)1,037,836,800 ways

Step-by-step explanation:

a. How many ways are there to choose 10 players to play the game?

We have to take note of a key word here which is CHOOSE. For question a, order does not matter.

Hence, we use the combination formula. This is given as:

C(n, r) = nCr = n!/r! (n - r)!

n = 13, r = 10

13C10 = 13!/10! (13 - 10)!

= 13!/ 10! × (3!)

= 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 / (10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1) × (3 × 2 × 1)

= 1716/6

= 286 ways.

b. How many ways are there to assign the 10 different positions by selecting players from the 13 who show up?

For question b as well, we take note of a key word which is ASSIGN. For question b, order is very important.

Therefore, the formula we use is the permutation formula.

P(n, r) = nPr = n!/(n - r)!

n = 13, r = 10

13P10 = 13!/ (13 - 10)!

= 13!/ 3!

= 13 × 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 / (3 × 2 × 1)

= 1,037,836,800 ways

1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6

0.85% : )

step-by-step explanation: