WILL CHOOSE BRAINLIEST Let Events A & B be described as follows: P(A) = watching a movie P(B) = going out to dinner The probability that a person will watch a movie is 62% and the probability of going out to dinner is 46%. The probability of watching a movie and going out to dinner is 28.52% Are watching a movie and going out to dinner independent events? Group of answer choices No, because the P(A)P(B) ≠ P(A and B). Yes, because the P(A)P(B) = P(A and B). No, because the P(A) + P(B) ≠ P(A and B). Yes, because the P(A) + P(B) is greater than 100%.

Yes, because the P(A)P(B) = P(A and B)

Step-by-step explanation:

Independent Events are events that occurs simultaneously i.e they occur at the same time. This means that the occurrence of one does not affect the other. If A and B are two events, for the to be independent then;

P(A and) = P(A)P(B)

Given: P(A) = watching a movie = 62% = 0.62

P(B) = going out to dinner = 46% = 0.46

The probability of watching a movie and going out to dinner will be

P(A and B)

P(A and B) = 0.62×0.46

P(A and B) = 0.2852

P(A and B) = 28.52%

Since the probability of watching a movie and going out to dinner is 28.52% which tallies with the question, hence it can be concluded that watching a movie and going out to dinner are independent events.

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

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