can anyone help me solve this !

x = 60/83

Step-by-step explanation:

Solve for x:

10 - (83 x)/6 = 0

Put each term in 10 - (83 x)/6 over the common denominator 6: 10 - (83 x)/6 = 60/6 - (83 x)/6:

60/6 - (83 x)/6 = 0

60/6 - (83 x)/6 = (60 - 83 x)/6:

(60 - 83 x)/6 = 0

Multiply both sides of (60 - 83 x)/6 = 0 by 6:

(6 (60 - 83 x))/6 = 6×0

(6 (60 - 83 x))/6 = 6/6×(60 - 83 x) = 60 - 83 x:

60 - 83 x = 6×0

0×6 = 0:

60 - 83 x = 0

Subtract 60 from both sides:

(60 - 60) - 83 x = -60

60 - 60 = 0:

-83 x = -60

Divide both sides of -83 x = -60 by -83:

(-83 x)/(-83) = (-60)/(-83)

(-83)/(-83) = 1:

x = (-60)/(-83)

Multiply numerator and denominator of (-60)/(-83) by -1:

x = 60/83

idk

step-by-step explanation:

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2