Which of the following expressions are equivalent to -\dfrac{9}{j}− j 9 minus, start fraction, 9, divided by, j, end fraction? Choose all answers that apply: Choose all answers that apply: (Choice A) A \dfrac{9}{-j} −j 9 start fraction, 9, divided by, minus, j, end fraction (Choice B) B -\dfrac{-9}{j}− j −9 minus, start fraction, minus, 9, divided by, j, end fraction (Choice C) C None of the above

b) well because you get well

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

40 minutes

step-by-step explanation:

add the time and multiply by 2