The three-dimensional figure shown consists of a cylinder and a right circular cone. The radius of the base is 10 centimeters. The height of the cylinder is 16 centimeters, and the total height of the figure is 28 centimeters. The slant height of the cone is 13 centimeters. Which choice is the best approximation of the surface area of the figure? Use 3.14 to approximate pi.

2,041 square centimeters

Step-by-step explanation:

surface area = (2 × π × r × h) + ((π × r) × (r+ (√(c² + r²+(π × r²)

where,

cylinder  base radius (r) = 10  cm

height of cylinder (h) = 16 cm

total height = 28 cm

cone height (c) = total height - height of cylinder = 28 - 16 = 12cm

π = 3.14

surface area = (2 × 3.14 × 10 × 16) + ((3.14 × 10) × (10+ (√(12² + 10²+(3.14 × 10²)

surface area = 1004.8 + (31.4 * 25.6) + 314

surface area = 2122.64 cm²

therefore the approximate surface area given is 2,041 square centimeters

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

i can't read the graph

step-by-step explanation: