In right triangle ΔABC (m∠C = 90°), point P is the intersection of the angle bisectors of the acute angles. The distance from P to the hypotenuse is equal to 4 in. Find the perimeter of △ABC if AB = 12 in.

the perimeter of ΔABC is 32in

Step-by-step explanation:

We know that intersection point of the angle bisectors refers to the incenter of the triangle,.

Given tmthe radius of 4inch for the centre of the incircle.

One of the properties of the incircle is that the distances (d) from vertex C to the nearest touchpoints are equal and have the value

In an incircle , the distances (d) along vertex C and touchpoints have equal value and can be expressed as

d = 1/2(a +b -c)

And a, b, c represent lengths of the sides

We were given the hypotenuse (c) as 12 in, with the radius of 4inch for the

distance from the right-angle vertex C to the incircle touchpoints .

We can determine the sum a+b as

4 = (1/2)(a+b -12) .

4/(1/2)= (a+b -12)

8= (a+b -12)

20=a+b

Which is the addition of length of the two legs of the triangle.

We can determine the perimeter which is the addition of the leg lengths as well as the hypotenuse length.

perimeter = 20 in + 12 in = 32 in

Therefore, the perimeter of ΔABC is 32in

idk

step-by-step explanation:

maybe try   if it is work from a book, if not try