Mathematics, 12.08.2020 08:01 lelen2021
Given that a is a multiple of 456, find the greatest common divisor of 3a^3+a^2+4a+57 and a.
Answers: 1
![=57[3(57)^2\times (8x)^3+(57)\times (8x)^2+4\times (8x)+1]](/tpl/images/0720/0390/5bca5.png)
![3a^3+a^2+4a+57=57[3(57)^2\times (8x)^3+(57)\times (8x)^2+4\times (8x)+1]](/tpl/images/0720/0390/29512.png)
is 57.
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Given that a is a multiple of 456, find the greatest common divisor of 3a^3+a^2+4a+57 and a....
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