If 0≤β<2π, find all values of β that satisfy the equation cos(2β)=√3/2

Step-by-step explanation:

Given the expression cos(2β)=√3/2 for 0≤β<2π, we are to find the value of β within the range that satisfies the equation.

Since cos id positive in the 4th quadrant, ,

Hence the value of that satisfy the equation are 15° and 345°

Converting to radians;

180° = πrad

15° = 15π/180 rad

15° = π/12 rad

345° = 345π/180

345° = 23π/12 rad

The values in radians are  π/12 rad and  23π/12 rad

i dont know

step-by-step explanation:

the reason i dont know is because i have not taken this class and for that reason i haven't learned this stuff

hope i could