Cot theta - cosec theta = P , then cot theta + cosec theta =

Recall

or, $\csc^2\theta-\cot^2\theta=1 \implies (\csc\theta+\cot\theta)(\csc\theta-\cot\theta)=1$

Now, $\cot \theta - \csc \theta = P$

$\implies (-P)(\csc\theta+\cot\theta)=1$

or $(\csc\theta+\cot\theta)=-\frac{1}{P}$

what's the question?

step-by-step explanation:

there is no question.

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a