ASAP PLEASE help me with this question! This is really urgent! No nonsense answers please.

Explanation:

Let point A be the center of the circle.

Arc DCF is 316 degrees. Arc FG is 20 degrees. Subtracting the arc measures gives 316-20 = 296 which is the measure of arc DCG, and by extension, it is the measure of reflex angle DAG. The acute angle DAG is 360-296 = 64 degrees

Triangle DAG is isosceles with AD = AG, so the base angles are ADG and AGD. Let's call each of these angles x for now. The sum of the three angles add to 180

x+x+64 = 180

2x+64 = 180

2x = 180-64

2x = 116

x = 116/2

x = 58

Therefore angle ADG is 58 degrees. It adds to angle ADB = 90 to get 90+58 = 148, which is the measure of angle BDG.

Note: angle ADB is 90 because tangent BD forms a right angle with the radius AD.

Another note: angle ADG is half that of the arc it cuts off, so in a sense it's similar to an inscribed angle

d 600 because 15*10*2=300

300+300=600

step-by-step explanation:

y=sec x is the correct answer

~batmans wife dun dun