Which of these is NOT discrete data: A. number of home-runs hit in a professional baseball game
B. air pressure in a car tire
C. cars per household in a town
D. number of pills in a container of vitamins

B, air pressure in a car tire.

Step-by-step explanation:

Discrete data is data which come in intervals, and isn't continuous.

The number of home runs can only go 0 -> 1 -> 2 -> 3, you can't have 2.5 or 3.2 home-runs.

The number of pills in a container can also only go 0 -> 1 -> 2. Again, can't have 0.7 pills.

The number of cars per household is also discrete. The number of cars in a household goes 0 -> 1 -> 2, you can't have half a car!

However, the air pressure is continuous. If you're increasing the air pressure, it'll (in theory) go from 0 -> 0.000...001 -> 0.000..002 etc. It doesn't "jump" from 0 pressure -> 1 pressure like the others, it goes smoothly. It can be any value.

So the air pressure isn't discrete data.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.