Use suitable identities to find the product of 1) (x-4) (x+10) 2) (3x+4) (3x +5) 3) (-3a +5b +4c)^2

Step-by-step explanation:

(x-4) (x+10)  ⇒ (x+a)(x+b)=x²+(a+b)x+ab

a=-4 , b=10

x²+(-4+10)x+-4(10)

x²+6x-40

(3x+4) (3x +5)

3(x+4/3) *3(x+5/3)  ⇒ identity : (x+a)(x+b)=x²+(a+b)x+ab  

a=4/3    b=5/3

3*3=9

9[x²+(4/3 +5/3)x+4/3(5/3)]

9[x²+9/3 x+20/9]

9x²+27x+20

(-3a +5b +4c)^2  ⇒  

suitable identity is (a+b+c)²= a² + b² + c² + 2ab + 2bc + 2ca

a=-3a , b=5b , c=4c

9a²+25b²+16c²- 30ab +40bc - 24ca

by definition, an arc subtended by a central angle of some given measure has the same measure. so .

i think the answer is true

step-by-step explanation: