Determine the convergence or divergence of the sequence with the given nth term. If the sequence converges, find its limit. (If the quantity diverges, enter DIVERGES.) an = 1/sqrt(n)

This sequence converges to 0.

Proof: Recall that

is to say that for any given , there is some for which for all .

Let . Then

as required.

i'm not entirely sure

step-by-step explanation:

if you ask home depot or lowe's they might be able to you out

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.