A player at a fair pays Rs. 100 to roll a dice. The player receives Rs. 50 if the number of dots facing up is equal to 5, Rs. 200 if the number is 6, but nothing otherwise. Find the expected value of the reward Y. What is the expected value of the gain? Find out the standard deviation of Y.

The dice has 6 options:

if the outcome is 5, player wins 50

if the outcome is 6, player wins 200

if the outcome is another number, the player does not win anything.

Now, remember that the expected value can be written as:

E = ∑xₙpₙ

where xₙ is the event n, and pₙ is the probability of that event.

for a dice, the probabilty for each number is 1/6

The expected value is:

E = (1/6)*(0 + 0 + 0 + 0 + 50 + 200) = 41.66

The expected gain will be E - 100 (because the player pays 100 in order to play)

Then the expected gain is:

G = 41.66 - 100 = -58.33

The standard deviation can be written as:

s = √( ∑(x - x)^2/n)

where x is the mean, in this case the mean is:

(200 + 50 + 4*0)/6 = 41.66  and n = 6.

s = √( (1/6)*(4*(0 - 41.66)^2 + (50 - 41.66)^2 + (200 - 41.66)^2) ) = 73

So we have a lot of standard deviation on Y.

first option

a function is a relation in which an input is paired with exactly one output.

so, let's find the right answer.

in our first option, our inputs are january, february, and march. the outputs are 30, 28, and 25. each input has it's own output. this is correct!

our second option we know is incorrect, because ms. valverade has two outputs, dogs and cats. this is not a function.

our third option is incorrect as well. the yellow square has two ouputs, the square and the triangle.

lastly, in our fourth option, we see the number 7 two times with a different output. therefore, this is not a function.

remember: each input must be paired with only one output!

answer: sine

step-by-step explanation: