Help and show work please.

Any rectangle is also a parallelogram (but not the other way around). So AB is parallel to CD. The angles BAC and ACD are alternate interior angles that are congruent due to the parallel sides mentioned.

(angle BAC) = (angle ACD)

3x+4 = x+28

3x-x = 28-4

2x = 24

x = 24/2

x = 12

So,

angle BAC = 3x+4 = 3*12+4 = 40 degrees

and

angle CAD = 90 - (angle BAC) = 90 - 40 = 50 degrees

With any rectangle, the four interior angles are always 90 degrees. So that's why angles BAC and CAD add to 90.

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