When six basketball players are about to have a free-throw competition, they often draw names out of a hat to randomly select the order in which they shoot. What is the probability that they shoot free throws in alphabetical order? Assume each player has a different name. P(shoot free throws in alphabetical order)=

Answer as a fraction = 1/720

Answer in decimal form (approximate) = 0.001388

Answer in percent form (approximate) = 0.1388%

Explanation:

Let A = 1 to indicate the number of ways to get the names to line up in alphabetical order.

There are B = 6*5*4*3*2*1 = 720 different ways to arrange the six people. Notice how I started at 6 and counted my way down to 1, multiplying all along the way. This can be shortened to factorial notation to say 6! = 720. Or you could use the nPr permutation formula to get the same result (use n = 6 and r = 6).

Once you have the values of A and B, we form the fraction A/B = 1/720 which is the probability of getting the names in alphabetical order.

If you need the answer in decimal form, then use your calculator to find

1/720 = 0.001388

which converts over to 0.1388%

answer: -8.2562234e+13