Find the sum of the infinite geometric series -27, -9, -3, … The ratio is /3 and u1 is -27

Work Shown:

a = -27 = first term

r = 1/3 = common ratio, note how this is between -1 and 1

We start with -27 and multiply by 1/3 each time to get the next term

S = infinite sum

S = a/(1-r), which only works because -1 < r < 1 is true

S = -27/(1-1/3)

S = -27/(2/3)

S = (-27/1) divided by (2/3)

S = (-27/1) times (3/2)

S = (-27*3)/(1*2)

S = -81/2

As you generate and add up the terms of the sequence, the infinite sum slowly starts to approach -81/2 = -40.5; we'll never actually achieve this sum exactly. Think of it as approaching an asymptote.

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!

hard

step-by-step explanation: