BRAINLIEST, 5 STARS, 50 POINTS AND THANKS IF ANSWERED CORRECTLY.

1. What are the solutions for x when y is equal to 0 in the following quadratic function?
y = x^2 + 4

2. What are the solutions for x when y is equal to 0 in the following quadratic function?
y = x^2 - 81

Thank you if you answered!

see explanation

Step-by-step explanation:

(1)

x² + 4 = 0 ( subtract 4 from both sides )

x² = - 4 ( take the square root of both sides )

x = ± = ± 2i ← complex solutions

(2)

x² - 81 = 0 ( add 81 to both sides )

x² = 81 ( take the square root of both sides )

x = ± = ± 9 ← real solutions

1. -2

2. 9

Step-by-step explanation:

1. 0 = x2 + 4

  -4 = x2

  = x

x = -2

2. 0 = x2 - 81

   81 = x2

    = x

 x = 9

    MARK IT BRAINLIEST!!!

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3