How does the multiplicity of a zero affect the graph of the polynomial function? Select answers from the drop-down menus to correctly complete the statements
The zeros of a ninth degree polynomial function are 1 (multiplicity of 3), 2, 4, and 6 (multiplicity of 4).
The graph of the function will cross through the x-axis at only
The graph
will only touch (be tangent to) the x-us at

the x-axis
At the zero of 2, the graph of the function will choose...

Step-by-step explanation:

Let the equation of a polynomial is,

Zeroes of this polynomial are x = a, b and c.

For the root x = a, multiplicity of the root 'a' is 2 [given as the power of (x - a)]

Similarly, multiplicity of the roots b and c are 1 and 3.

Effect of multiplicity on the graph,

If the multiplicity of a root is even then the graph will touch the x-axis and if it is odd, graph will cross the x-axis.

Therefore, graph will cross x -axis at x = b and c while it will touch the x-axis for x = a.

In this question,

The given polynomial is,

Degree of the polynomial = 3 + 1 + 1 + 4 = 9

The graph of the function will cross through the x-axis at x = 1, 2, 4 only, The graph will touch to the x-axis at 6 only.

At the zero of 2 , the graph of the function will CROSS the x-axis.

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !