Mathematics, 12.08.2020 06:01 Izzyfizzy

2. A 10 Mg truck hauls a 20 Mg trailer. If the unit starts from rest on a level road with a tractive force of 20 kN between the driving wheels of the truck and the road, calculate the
acceleration of the unit and the tension in the horizontal draw-bar.
Drawbar
20 Mg Trailer
10 Mg Truck
a=0.667 m/s2
T= 13.3 KN
Oro
W

Answers: 2

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Answer from: nique1024

The acceleration is 0.00067m/s^2, while the tension on the horizontal bar is 13.4 N

The given parameters are:

$\mathbf{m = 10Mg}$ -- mass of the truck

$\mathbf{M = 20Mg}$ -- mass of the trailer

$\mathbf{F_T = 20kN}$ --- tractive force

Start by calculating the total mass

$\mathbf{M_T = m + M}$

So, we have:

$\mathbf{M_T = 10Mg + 20Mg}$

$\mathbf{M_T = 30Mg}$

Convert to kilograms

$\mathbf{M_T = 30 \times 10^3kg}$

$\mathbf{M_T = 30000 kg}$

Force is calculated as:

$\mathbf{F =ma}$

So, we have:

$\mathbf{20kN =30000kg \times a}$

Divide both sides by 30000

$\mathbf{a = 0.00067ms^{-2}}$

The tension on the horizontal bar (i.e. the 20 Mg trailer) is:

$\mathbf{T=ma}$

So, we have:

$\mathbf{T=20Mg \times 0.00067ms^{-2}}$

Rewrite as:

$\mathbf{T=20 \times 10^3 kg \times 0.00067m/s}$

$\mathbf{T=13.4N}$

Hence, the acceleration is 0.00067m/s^2, while the tension on the horizontal bar is 13.4 N

Read more about force and acceleration at:

link

Answer from: rainbowsadie7140

The acceleration on the unit is 0.667 m/s^2

The tension on the draw-bar is 13.34 kN

Step-by-step explanation:

The mass of the truck = 10 Mg = 10 x 10^3 kg

The mass of the trailer = 20 Mg = 20 x 10^3 kg

Tractive force from the truck = 20 kN = 20 x 10^3 N

The total mass of the unit = 10 Mg + 20 Mg = 30 Mg = 30 x 10^3 kg

The tractive force on the unit will produce an acceleration that is given as

F = ma

where

F is the tractive = 20 x 10^3 N

m is the mass of the unit = 30 x 10^3 kg

a is the acceleration of the unit = ?

substituting into the equation

20 x 10^3 = 30 x 10^3 x a

a = (20 x 10^3)/(30 x 10^3) = 0.667 m/s^2

the tension on the draw-bar T is gotten from considering only the mass that is pulled by the draw-bar which is 20 Mg

The acceleration on the unit = 0.667 m/s^2

The drawn mass = 20 Mg = 20 x 10^3 kg

The tension on the draw bar = ma = 20 x 10^3 x 0.667 = 13340 N

= 13.34 kN

Answer from: Quest

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote

Answer from: Quest

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.