Find the equation of the line of gradient 3 which passes through the point (0, 2).

Step-by-step explanation:

To find the equation of the line given a point and the gradient, the formula to use is

y - y1 = m(x - x1)

where

m is the gradient and

( x1 , y1) is the point

From the question

The point is (0 , 2)

The gradient is 3

Substitute the values into the above formula

That's

y - 2 = 3( x - 0)

y - 2 = 3x

The final answer is

Hope this helps you

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

step-by-step explanation: