According to a government study among adults in the 25- to 34-year age group, the mean amount spent per year on reading and entertainment is $1,999. Assume that the distribution of the amounts spent follows the normal distribution with a standard deviation of $574. (Round your z-score computation to 2 decimal places and final answers to 2 decimal places.) What percent of the adults spend more than $2,550 per year on reading and entertainment?

The probability is  

Step-by-step explanation:

From the question we are told that

   Th The population mean

    The  standard deviation is  

    The  values considered is  

Given that the distribution of the amounts spent follows the normal distribution then the  percent of the adults spend more than $2,550 per year on reading and entertainment is mathematically represented as

Generally  

So

substituting values

From the normal distribution table the value of is  

Thus  

i do not know the answer

step-by-step explanation: