Alexander bought a box of crackers at the store. He ate half of the crackers in the box on Monday, and he ate 1/2 of what was left on Tuesday. On Wednesday, he ate 1/3 of what was left after he was finished eating the crackers on Tuesday. 1) What fractional part of the total crackers originally in the box did Alexander
eat on Wednesday?
2) what fractional part of the total crackers originally in the box are left. 3) if there are 4 crackers left in the box after Alexander finished eating crackers on wensday, how many crackers were in the box before it was opened. (Please help!)

1. 1/12x

2.1/6x

3. 18

Step-by-step explanation:

Let

x=number of crackers in the box

On Monday, Alexander are 1/2 of the crackers

1/2 of x

=1/2x

Remaining

x-1/2x=2x-1/2

=1/2x

Tuesday=1/2 of what was left

=1/2 of 1/2x

=1/2×1/2x

=1/4x

Remaining

1/2x-1/4x

=2x-x/4

=1/4x

Wednesday=1/3 of what was left

=1/3 of 1/4x

=1/12x

Remaining

1/4x-1/12x

=3x-x/12

=2/12x

=1/6x

1. What fractional part of the total crackers originally in the box did Alexander eat on Wednesday?

1/12x

2. what fractional part of the total crackers originally in the box are left.

1/6x

3. if there are 4 crackers left in the box after Alexander finished eating crackers on wensday, how many crackers were in the box before it was opened.

1/6x=3

Divide both sides by 1/6

1/6x ÷ 1/6 = 3 ÷ 1/6

x=3÷1/6

=3 × 6/1

=18

x=18

answer: 0,6

step-by-step explanation:

this would make it the y intercept.