If m(2x−3)+n(x+1)=5x for all real numbers x, where m and n are constants, what is the value of m?

m = 1

Step-by-step explanation:

From the question given,

m(2x − 3) + n(x + 1) = 5x for all real numbers x.

Since x is a real number, we can obtain the value of m as follow:

Let x = 1

m(2x − 3) + n(x + 1) = 5x

m(2×1 − 3) + n(1 + 1) = 5×1

m(2 – 3) + n(2) = 5

m(– 1) + n(2) = 5

– m + 2n = 5 (1)

Let x = 2

m(2x − 3) + n(x + 1) = 5x

m(2×2 − 3) + n(2 + 1) = 5×2

m(4 – 3) + n(3) = 10

m(1) + n(3) = 10

m + 3n = 10 (2)

– m + 2n = 5 (1)

m + 3n = 10 (2)

Solve by elimination method

Add equation 1 and 2

– m + 2n = 5

+ (m + 3n = 10)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

5n = 15

Divide both side by 5

n = 15/5

n = 3

Substitute the value of n into any of the equation to obtain the value of m. Here, we shall substitute n into equation 2.

m + 3n = 10

m + 3(3) = 10

m + 9 = 10

Collect like terms

m = 10 – 9

m = 1

Therefore, the value of m is 1

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer