A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 4 centimeters long, and the height of the equilateral triangle is 3.5 centimeters. The pyramid's slant height is 8 centimeters. What is its surface area?

The surface area is 55 cm².

Step-by-step explanation:

The formula to compute the surface area of the triangular pyramid is:

Here h is the slant height.

Compute the Base perimeter as follows:

Perimeter of the equilateral triangle = 3 × side

                                                            = 3 × 4

                                                            = 12 cm

Compute the Base area as follows:

Area of the equilateral triangle = 0.50 × side × height

                                                    = 0.50 × 4 × 3.50

                                                    = 7 cm²

Compute the surface area as follows:

Thus, the surface area is 55 cm².

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: ur v dumb

step-by-step explanation: