The distribution of city championship wins shared by 3 HS girls basketball teams in Clayton, MO is as follows: Rockefeller HS 12, Clayton West 20, Clayton South 7. Rounded to the nearest 10%, approximately what percentage of the total wins does each team have?

Rockefeller HS = 31%

Clayton West = 51%

Clayton South = 18%

Step-by-step explanation:

Given the following:

Championship wins shared by 3 basketball teams :

Rockefeller HS = 12

Clayton West = 20

Clayton South = 7

Percentage of total wins each team has :

Total number of wins = (12 + 20 + 7) = 39 wins

Percentage wins :

[(Number of wins per team) / total number of wins)] × 100

Rockefeller HS:

(12 / 39) * 100 = 30.769% = 31%

Clayton West :

(20/39) * 100 = 51.28% = 51%

Clayton South:

(7/39) * 100 = 17.948% = 18%

i need more information

step-by-step explanation:

so, converting firstly the mixed fractions to improper fractions and then "adding".