Locate the points of discontinuity in the piecewise function shown below. |-(x + 1)2 + 2; - < x < -1
f(x) = {-4 + 2; -1 < x <2
VE - 1;
2 O A.
x= -1 and 2
OB.
x = 2
Oc.
x= -1
OD.
no points of discontinuity
Reset
Next

Solve the equation using the zero-product property. -3n(7n - 5) = 0 a. 0, -5/7 b. -1/3, -5/7 c. -1/3, 5/7 d. 0, 5/7

Runner ran 1 4/5 miles on monday and 6 3/10 on tuesday. how many times her monday’s distance was her tuesdays distance

The value of x in this system of equations is 1. 3x + y = 9 y = –4x + 10 substitute the value of y in the first equation: combine like terms: apply the subtraction property of equality: apply the division property of equality: 3x + (–4x + 10) = 9 –x + 10 = 9 –x = –1 x = 1 what is the value of y?