Where does the graph of y = sin x from x = 0 to x = 2π start? A. at its minimum B. at an x–intercept C. at its maximum D. between an x–intercept and its maximum

  B. at an x–intercept

Step-by-step explanation:

You can find a graph of the sine function in numerous places.

  y = sin(0) = 0

  y = 0 for x = 0

so, on the given interval, it starts at an x-intercept.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option