Mathematics, 18.08.2019 18:30 JN02

What is the indefinite integral of 6sin(3t) dt?

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Answer from: bighomie28

$\displaystyle \int {6sin(3t)} \, dt = -2cos(3t) + C$

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Integration

Integrals[Indefinite Integrals] Integration Constant C

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \int {6sin(3t)} \, dt$

Step 2: Integrate Pt. 1

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int {6sin(3t)} \, dt = 6\int {sin(3t)} \, dt$

Step 3: Integrate Pt. 2

Identify variables for u-substitution.

Set u: $\displaystyle u = 3t$ [u] Differentiate [Basic Power Rule, Multiplied Constant]: $\displaystyle du = 3 \ dt$

Step 4: integrate Pt. 3

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle \int {6sin(3t)} \, dt = 2\int {3sin(3t)} \, dt$ [Integral] U-Substitution: $\displaystyle \int {6sin(3t)} \, dt = 2\int {sin(u)} \, du$ [Integral] Trigonometric Integration: $\displaystyle \int {6sin(3t)} \, dt = -2cos(u) + C$ Back-Substitute: $\displaystyle \int {6sin(3t)} \, dt = -2cos(3t) + C$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Answer from: Quest

you forgot an image

step-by-step explanation:

Answer from: Quest

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !
Find the slope of the line parallel to each given line

Find the slope of the line parallel to each given line

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