Find the term of each sequence.

32, 80, 200, ...5th term

t5 = 1250

Step-by-step explanation:

Each term is derived by multiplying the previous term by 2.5

t2 = t1 * 2.5

t2 = 32 * 2.5

t2 = 80

tn = a*b^(n - 1)

t3 = 32*2.5^2

t3 = 200

That's just to test the formula. It does work.

t5 = 32*2.5^(5 -1)

t5 = 32*2.5^4

t5 = 1250

idk but i found this "the graph of y = f(x-2) is the graph of y = f(x) translated two units rightward.  

so, since the point (9,2) lies on the graph of y = f(x), the point (11,2) lies on the graph of y = f(x-2)."

step-by-step explanation:

link is

c - they will have the same distribution

step-by-step explanation:

this is the only one that could make sense. : )